Video About English Chemistry


FARADAY'S LAW 1

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https://www.youtube.com/watch?v=VMXNJZneaBc

Faraday's Law   States the relationship between the amount of electricity used with the mass of the substances produced in both the cathode and the anode in the electrolysis process. Sound   Faraday's Law 1   "The mass of the substances formed on each electrode is proportional to the electric current flowing in the electrolysis" while the sound   Faraday's Law 2   "The mass of various substances deposited on each electrode by an equivalent amount of electric current will be proportional to the equivalent weight of each of these substances"

Michael Faraday is a British scientist who is an expert in chemistry and physics and earned the nickname "Father of Electricity " because thanks to his electrical efforts into technology that much point. He studied various fields of science, including electromagnetics and electrochemical fields. He also invented a tool that would later become a Bunsen burner, which is used in almost all science labs as a practical heat source. He was born on September 22, 1791 and died on August 25, 1867. He is known as a pioneer in researching about electricity and magnetism, even many of the scientists who say that he is a great researcher of all time. Some of the concepts he derived directly from experiments, such as electrolysis, have become an idea in modern physics.

Faraday observed electrolysis events through various experiments that he did. In his observations if a direct electric current is passed into an electrolyte solution, resulting in a chemical change in the solution. So Faraday discovered the relationship between the mass that was liberated or precipitated by the electric current. This relationship is known as Faraday's Law .

According to Faraday: The amount of mass (mass) of the substance produced (precipitated) on the electrode is proportional to the amount of electrical charge (Coulumb) supplied through the electrolyte solution. The mass of the material liberated or precipitated by an electric current is proportional to the equivalent weight of the substances. From the above two statements, it is simplified into the equation:
M = eit / F
Where:
M = mass of substances in grams
E = equivalent weight in gram = atomic weight: valence
I = strong current in Ampere
T = time in seconds
F = Faraday

Faraday concluded that One faraday is the amount of electricity required to produce one equivalent of the substance on the electrode.
1 electron charge = 1.6 x 10-19 Coulomb
1 mole of electron = 6,023 x 1023 eletron
The charge for 1 mol eletron = 6,023. 1023 x 1.6. 10 -19 = 96.500 Coulomb = 1 faraday.

Faraday's Law I
The sound of Faraday's law is "The mass of matter formed on each electrode is proportional to the electric current flowing in the electrolysis"
M = e. I. T / 96.500
Q = i. T
Where:
M = mass of the resulting substance (gram)
E = weight equivalent = Ar / Valence = Mr / Valence
I = strong electric current (amper)
T = time (seconds)
Q = electric charge (coulomb)
example faraday's Law 1
0.2 ampere electrical current is passed for 50 minutes into an electrolytic cell containing CuCl2 solution. Calculate the Cu precipitate formed on the cathode. (Ar Cu = 63,5)

Answer:

Calculate the precipitate Cu, wCu, using the formula:

WCu = (1/96500) x I x t x MECu = where ME = Ar / biloks

Is known:

Current, I = 0.2 A;

Time, t = 50 minutes = 50 x 60 seconds = 3,000 seconds

Find the MECu value by writing the Cu reduction reaction:

Cu2 + (aq) + 2e- → Cu (s); MECu = Ar / biloks = 63,5 / 2 = 31,75

Thus, it is obtained:

WCu = (1 / 96.500) x 0.2 A x 3,000 seconds x 31.75 = 0.197 g.
 
 

Komentar

  1. how to easy different faraday's law 1 and faraday's law 2 ?

    BalasHapus
    Balasan
    1. First it was seen from the sound of 1 different Faraday with Faraday 2 and the second is seen from the formula is different.

      Hapus
  2. in Na2SO4 solution, write the cathode and anode reaction ?

    BalasHapus
    Balasan
    1. The reaction occurs: Na2SO4 (aq) 2Na + (aq) + SO42-
      Cathode (C): 2H2O (l) + 2e 2OH- (aq) + H2 (g)
      Anode (C): 2H2O (l) 4e- + 4H + + O2 (g)
      Since the cathode and the anode react is water, the longer the water gets reduced so that needs to be added. Note that although the water react, does not mean Na2SO4 electrolyte is not necessary. The electrolyte is useful as a conductor of electric current.

      Hapus
  3. Why in the instance of time unit is changed to sekon ?

    BalasHapus
    Balasan
    1. Because it is the international unit of time that the unit is second. And units of time (seconds) can not be changed

      Hapus
  4. Give an example of electrolyte and nonelectrolyte?

    BalasHapus
    Balasan
    1. Example Electrolytes: H2SO4 = Sulfuric Acid NaCl = Sodium Chloride KOH = Potassium Hydroxide CH3COOH = Vinegar (Acetic Acid) HCl = Hydrochloric Acid
      Sample Solution Non-Electrolytes: NH3 = Ammonia, CO (NH2) 2 = Urea C12H22O11 = Sucrose C2H5OH = Alcohol (Ethanol ) CH 3 OH = Alcohol (methanol)

      Hapus
  5. In his observations if the electric current is directly passed to the electrolyte solution, resulting in chemical changes in the solution. What caused it?

    BalasHapus
    Balasan
    1. Because the electrolyte solution containing free ions. These ions and can give or receive electrons, so electrons can flow through the solution.

      Hapus

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